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Vijay Singh chauhan Asked a Question
September 4, 2021 6:32 ampts 30 pts
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  • Swapnajit das
    f(a) = a, f(b) =b ,now in [a,(a+b)/2] applying mean value theorem we get{ f(a+b)/2 - f(a)}/{(b-a)/2 = f'(C1) in same way, applying on [a+b/2, b] we get ,f'(C2) = {f(b) -f(a+b)/2}/{...
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  • Irfan thankyou
    see the attachment if any doubt then feel free to ask
    • cropped8301290557496884047.jpg
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