Pravansu Panda posted an Question
July 21, 2021 • 20:42 pm 30 points
  • IIT JAM
  • Chemistry (CY)

12. a 2.24l cylinder of oxygen at 1 atm and 273 k is found to develop a leakage. when the leakage was plugged the pressure dropped to 570 mm of

12. A 2.24L cylinder of oxygen at 1 atm and 273 K is found to develop a leakage. When the leakage was plugged the pressure dropped to 570 mm of Hg. The number of moles of gas that escaped will be : (a) 0.025 (b) 0.050 (c) 0.075 (d) 0.09

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    Priyanshu kumar Best Answer

    option A is correct Original pressure of Hg = 760 drop in pressure = 570 change in pressure= 760-570 = 190mm = 190/760 atm PV = nRT n = P V / RT = 190 x 2.24 / 760 x 0.821 x 273 = 0.0249 moles

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