• Want FREE Counselling for Exam Preparation?
###### Call Us
800-355-2211

Speak With a Friendly Mentor.

###### Pravansu Panda posted an Question
July 21, 2021 • 20:42 pm 30 points
• IIT JAM
• Chemistry (CY)

## 12. a 2.24l cylinder of oxygen at 1 atm and 273 k is found to develop a leakage. when the leakage was plugged the pressure dropped to 570 mm of

12. A 2.24L cylinder of oxygen at 1 atm and 273 K is found to develop a leakage. When the leakage was plugged the pressure dropped to 570 mm of Hg. The number of moles of gas that escaped will be : (a) 0.025 (b) 0.050 (c) 0.075 (d) 0.09

1 Answer(s) Answer Now
• 0 Likes
• 1 Comments
• 0 Shares
• ##### Priyanshu kumar Best Answer

option A is correct Original pressure of Hg = 760 drop in pressure = 570 change in pressure= 760-570 = 190mm = 190/760 atm PV = nRT n = P V / RT = 190 x 2.24 / 760 x 0.821 x 273 = 0.0249 moles

### Do You Want Better RANK in Your Exam?

Start Your Preparations with Eduncle’s FREE Study Material

• Updated Syllabus, Paper Pattern & Full Exam Details
• Sample Theory of Most Important Topic
• Model Test Paper with Detailed Solutions
• Last 5 Years Question Papers & Answers