Rajat jain Asked a Question
June 25, 2020 4:07 pmpts 50 pts
12 The value of the integral I =f(3y+ 2z )dx + (6x - 10z) y dy + (4x2 -5y ) dz along the portion from (1, 0, 1) to (3, 4, 5) of the curve C, which is the intersection of the two surfaces z = x +y and z =y + 1 equals to
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  • Deepak singh
    since ∆×F = 0 does implies F is conservative field and find scalar potential . now path will depend on initial and final points
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  • Deepak singh
    see attached
    • cropped1692443740.jpg
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    Deepak singh
    if any doubt please ask
  • P Choursiya thankyou
    see attachment
    • cropped958635541785902311.jpg
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