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Nilanjan Bhowmick AIR 3, CSIR NET (Earth Science)
- IIT JAM
- Chemistry (CY)
120 g mg was burnt in air to give a mixture of mg0 and mg3n2. the mixture is now dissolved in hci to form mgcl2 and nh4ci, if 107 grams nh4cl is produced. then
120 g Mg was burnt in air to give a mixture of Mg0 and Mg3N2. The mixture is now dissolved in HCI to form MgCl2 and NH4CI, if 107 grams NH4Cl is produced. Then the moles of MgCl2 formed is: (Atomic wt.: Mg = 24, N = 14, Cl = 35.5)] (A) 3 moles (B) 6 moles (C) 5 moles (D) 10 moles
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Suman Kumar![best-answer]()
see this
sir ni aara smjh me
Do back calculation
initially 5 mole mg hai and 2 mole NH4Cl produce hua hai
2 Mole NH4CL ke liye ek mole Mg3N2 chaiye
1 mole Mg3N2 ke liye 3 mole Mg chaiye. Initially 5 mole Mg tha . So balance 2 mole Mg bacha hai