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120 g of solution containing 40% by mass of nacl are mixed with 200 g of a solution containing 15% by mass nacl. determine the mass percent of sodium chloride i
120 g of solution containing 40% by mass of NaCl are mixed with 200 g of a solution containing 15% by mass NaCl. Determine the mass percent of sodium chloride in the final solution : (A) 24.4% What is the molality of the above solution? (B) 78% (C) 48.8% (D) 19.68%6 (A) 4.4 m (B) 5.5 m (C) 24.4 m (D) None
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Dinesh khalmaniya 1![best-answer]()
option A So first we will calculate the amount of NaCl in the first solution: w(NaCl) = m(NaCl)/ m(solution) 40% = m(NaCl)/ 120g 40/100 = m(NaCl)/ 120g m(NaCl) = 120×40/ 100 m(NaCl) = 48g After this we will calculate the amount of NaCl in the second solution: w(NaCl) = m(NaCl)/ m(solution) 15% = m(NaCl)/ 200g 15/100 = m(NaCl)/ 200g m(NaCl) = 15×200/ 100 m(NaCl) = 30g Now when we now the amounts of sodium chloride in each of the solutions, we can say that the final solution will be 320 (120+200)g containing 78(48+30)g of sodium chloride. To find the mass percent of NaCl in this final solution, we will use the formula, we used above: w(NaCl) = m(NaCl)/ m(solution) w(NaCl) = 78g/ 320g w(NaCl) = 0.24375 w(NaCl) = 24.375% w(NaCl) = 24.4% So the mass percent of sodium chloride in the final solution is 24.4%