IIT JAM
Ashwini Asked a Question
July 26, 2020 4:38 pmpts 30 pts
  • IIT JAM
  • Mathematics (MA)

14. let the sequence < s, > and < ,> are divergent. (a) the sequence < s, + 1, > may or may not be convergent (b) the sequence < s, +1,>is always divergent (c)

14. Let the sequence < S, > and < ,> are divergent. (a) the sequence < S, + 1, > may or may not be convergent (b) the sequence < S, +1,>is always divergent (c) the sequence may or may not be convergent (a) the sequence < S, t, > is always divergent
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  • Shashi ranjan sinha thankyou
    see
    • cropped2353768793539569711.jpg
    • cropped1862147130770207991.jpg
    Likes(0) Reply(11)
    Vishal goswami
    1 is not a dgt sequence.
  • Vishal goswami thankyou
    option a and d are right. see attachment
    • cropped7636675100834383397.jpg
    Likes(0) Reply(4)
    Shashi ranjan sinha
    Ur proof for the option d has mistake.... u can't conclude that divergence of a sequence Sn implies that Sn+1 /An > 1
  • Deepak singh
    product of two divergent sequence may be convergent
    Likes(0) Reply(3)
    Vishal goswami
    please give any example.
  • Shashi ranjan sinha
    options a,c are correct and b,d are incorrect
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  • Deepak singh
    A and C are correct..
    Likes(0) Reply(0)
  • Sourav Jana
    we can't define option a,b,c,d in proper way. cause their arises various types of conclusion depending on which way we choose this two sepuence
    Likes(0) Reply(0)
  • Sourav Jana
    I think question needs to be more clear
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