Lalthazuala posted an Question
December 06, 2020 • 00:46 am 30 points
  • IIT JAM
  • Mathematics (MA)

15. the differential equation whose solution is given by xyz =c is (a) yzds +azdy + xydz =0 b) xdx+ ydy + zdz = 0 (c) log xdr+log ydy + log zdz = 0 (d) log dx +

15. The differential equation whose solution is given by xyz =c is (a) yzds +Azdy + xydz =0 b) xdx+ ydy + zdz = 0 (c) log xdr+log ydy + log zdz = 0 (d) log dx + log-dy + log-d =0

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    Satpal singh best-answer

    option 1 is true. divide by xyz and integrate you will get logx +logy+logz=logc that implies xyz=c

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