IIT JAM
Rajat jain Asked a Question
June 2, 2020 11:53 pmpts 50 pts
  • IIT JAM
  • Mathematics (MA)

18 1 18 1 1 18 0+9 1 de -10 dt -9 1 in(-9)-in(+9)= -10t +c 18 18 1 in -9=-10°t+c 18 0+9 to find the value of c, e(0)= 1000

WHY ln IS USED HERE INSTEAD OF log ?????? 18 1 18 1 1 18 0+9 1 de -10 dt -9 1 In(-9)-In(+9)= -10t +C 18 18 1 In -9=-10°t+c 18 0+9 To find the value of c, e(0)= 1000
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  • Vaishnavi rajora thankyou
    since thitha is not known....if it is known we can find it by calculator but here we have to use cinditions.
    • cropped2053493102764998424.jpg
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    Vaishnavi rajora
    hope it will help u
  • P Choursiya thankyou
    for finding value of c you have to use calculator
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    Rajat jain
    ya we have to use calculator