Prachi Kashyap posted an Question
January 31, 2022 • 18:07 pm 30 points
  • IIT JAM
  • Mathematics (MA)

19. let v be a vector space of all real valued functions from (-1, 1)> r. w-fevif(x) = f(-x), vx e (0, 1)) w, ={fe vif(-x) =-f (x), vx e (0, 1)} let t: v>v line

19. Let V be a vector space of all real valued functions from (-1, 1)> R. W-feVIf(x) = f(-x), Vx e (0, 1)) W, ={fe VIf(-x) =-f (x), Vx e (0, 1)} Let T: V>V linear operator such that T(w, + uw,) = w, - w, Vw, e W, w, e W2 then choose the incorrect? (a) T is not Invertible (b) T is Involuntary (c) ker(T - I)n ker (T + I) = {0} (d) Im(T-I)n Im(T + I)= {0}

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    Piyush pachauri best-answer

    This is reflection. T^2=I T is invertible because it doesn't have 0 Eigen values , possible Eigen values are 1 and -1

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