Gokul Asked a Question
November 21, 2020 5:28 pmpts 30 pts
-2 2-33 The matrix has M= 21 -6 cigen values -3,-3,5. An cigen -2 0 vector corresponding to the cigenvalue 5 is [1 2 -].One of the cigen vectors of the matrix M' is CA)[1 8 -1]' (B) [1 2
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  • Piyush
    Any doubt then you can ask
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  • Piyush thankyou
    Option B is correct. As M^3x = M^2(Mx) = M^2(lembda x) = lembda^3 x it implies x is Eigen vector corresponding to 125 in M^3.
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