Payal posted an Question
July 14, 2020 • 16:40 pm 30 points
  • IIT JAM
  • Chemistry (CY)

2. among the following, the unstable carbonyl species is: (b) mn(co)sl (d) mn(co)s (a) mn(co),cl )ma(co)s]*

2. Among the following, the unstable carbonyl species is: (b) Mn(CO)sl (d) Mn(CO)s (a) Mn(CO),cl )Ma(CO)s]*

2 Answer(s) Answer Now
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  • comment-profile-img>
    Priyanshu kumar

    https://drive.google.com/file/d/14JzkbN7-i3FhieuFTPrrw2DRSWWA0StM/view?usp=drivesdk meghna for organometallic chemistry part read this

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    Thank you sir

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    welcome😊

  • comment-profile-img>
    Dinesh khalmaniya 1

    Mn(CO)5]+ also unstable due to not following EAN rule. it has 16 e. so according to me option C and D are correct. but if we see Mn(CO)5 can be stabilized by dimerization so if only one option i.e., C is correct

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    please accept the answer if you got it 🙏🙏

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    what's the option given in your booklet?? option C??

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    option D

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    then option C must be wrong because it also doesn't follow EAN

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    wait I'm checking again

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    ok sir

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    i got the ans why C is stable actuallyMn+= 3d54s1; in presence of CO, effective configuration =3d64s0.  Three lone pair for back bonding with vacant orbital of C in CO. 

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    sir, I can't understand the above line that 'Three lone pair for backbonding with vacant orbital of C in CO. Could you please explain this??

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    wait

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    Meghna there is something wrong in option C. it's actually [Mn(CO)6]+ so it follow EAN

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    where did you get this question??

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    From telegram app

  • comment-profile-img>
    Dinesh khalmaniya 1 Best Answer

    check it

    cropped5733384279322443629.jpg
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    got it??

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    EAN = valence electrons + epectrons given by ligand. here valence electrons are 7 + electrons given by 5 CO (5×2= 10) + 1 Cl (1×1) = 18

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    thank you sir

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    you welcome

  • comment-profile-img>
    Dinesh khalmaniya 1

    Mn(CO)5 is unstable compound because it have 17 electrons so it doesn't follow EAN . to stabilize, it needed 1 electron so it dimeriswd to form Mn2(CO)10 and it follow 18 electron rule.

  • comment-profile-img>
    Priyanshu kumar best-answer

    option D is right

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    but option C also doesn't obey 18 electron rule...it obey 16 electron rule so it is stable

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    you told that option C doesn't obey 18 e rule then how it can be stable

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    yes here it obey 16 electron rule...both this rule increases stability meghna

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    please accept the answer if it helps 😊🙏

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