2 moles of NH, & 1 mol of HCl are kept in 8.21 L container. The temperature is 300 K. Caleulate the tnal pressure afer the reaction. Given NH,C! is solid. (a) 0.5 atm (b) 1 atm (c) 2 atm (d) 4 atm
Ans 3 atm
here 2 mole of NH3 + 1 mole of HCl---> 1 mole of NH4Cl so pressure is due to remaining 1mole of NH3
PV = nRT
P = nRT/v
P = 1 × 0.0821×300/8.21
P = 3 atm
as you proceed logically you see here,it is asking final pressure after reaction and finally NH4CL is formed which is solid so it posses no any pressure..So here we take standard p...