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- IIT JAM
- Chemistry (CY)
20. naci, kci, nabr and kbr crystalline in fc lattices. their anion and cation touch along the edge of unit cell. the dimensions of their unit cells are 562.8 p
20. NaCI, KCI, NaBr and KBr crystalline in FC lattices. Their anion and cation touch along the edge of unit cell. The dimensions of their unit cells are 562.8 pm, 627.7 pm, 596.2 pm, and 658.6 pm, respectively. From these data, what can you say about the size of the ionic radii (within an error of about 5%)?
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Priyanshu kumar Best Answer
I think you can proceed with this formula for all these you find r+ and r- and check the various options...little bit lengthy calculations part
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calculate this shristy..check whether ans comes or not
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Calculate kiye h sir
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will option c is correct ??
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but option a is given right
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wait let me calculate after this
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ok sir
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Calculation gets lengthy but when you analysing the equations you get that both the radius of cations and anions are nearly depend on each other
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ok sir thanks
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welcome shristy😊
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Amol ashok pawar![best-answer]()
Option C is correct As they both depends on each other. The nature of alkali metal and the halogen both plays a equal parts in deciding the ionic radii
option a is given
is the option given is wrong ???
Although neither atoms nor ions have sharp boundaries, they are sometimes treated as if they were hard spheres with radii such that the sum of ionic radii of the cation and anion gives the distance between the ions in a crystal lattice.
I strongly believe that option C is correct. answer key of certain classes are just the opinion of that particular person who is writing a book. I would recommend to always check the official answer key given by iit or csir
ok sir