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Roni pramanik Asked a Question
November 10, 2020 3:27 pmpts 30 pts
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  • Suman Kumar
    Both rings become anti aromatic. Such kind of compound show Quasi aromatic. They become aromatic by breaking the double bond between two rings.
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    Suman Kumar
    Hence option C is correct
  • Priyanshu kumar Best Answer
    Both rings become anti aromatic. Such kind of compound show Quari aromaticity. They become aromatic by breaking the double bond between two rings. As (III) become antiaromatic aft...
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    Priyanshu kumar
    option C is correct
  • Dinesh khalmaniya thankyou
    option C Here check the stability of compounds. I and II become Aromatic in ionic form so here only single bond exist. in I there is small rings so we know the small rings are more...
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    Roni pramanik
    sir I thinking same concept but ans is c ... why ?