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Anuradha Bhogaonkar posted an Question
May 16, 2020 • 13:23 pm 30 points
  • IIT JAM
  • Chemistry (CY)

25ml of a solution of 0.35 mol l' sodium hydroxide was titrated against a solution of sulphuric acid, according to the following equation: h:5o 2naoh na,so 2h:0

25ml of a solution of 0.35 mol L' sodium hydroxide was titrated against a solution of sulphuric acid, according to the following equation: H:5O 2NaOH Na,SO 2H:0 CDPS 502 Theory Assignment-51 2020 OAra Department of Applied Sciences and Social Practice Ara Institute of Canterbury Ltd The following table shows the results obtained during the titration: Titre 1 9.45 ml Titre 2 9.55 mL Titre 3 9.20 mL Titre 4 9.50 ml Titre 5 9.45 mL Titre 6 9.65 mt VIH,S0.) 3.3 Calculate the pH of the 0.35 mol L sodium hydroxide (remember to show your working) (2 marks)

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