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###### Bruce Wayne posted an Question
May 07, 2020 • 16:12 pm 30 points
• IIT JAM
• Physics (PH)

# 2t r sin 0 de dr ans. ta jo jo 27t r sin 6 d0 dr ans. twa 3 jo jo rcos 8 dr de jo ans. t rdr de, over the area bounded between the circles r =2 cos 6 and r = 4

2t r sin 0 de dr Ans. Ta Jo Jo 27t r sin 6 d0 dr Ans. TWa 3 Jo Jo rcos 8 dr de Jo Ans. T rdr de, over the area bounded between the circles r =2 cos 6 and r = 4 cos 6. Ans. 4 ul W.. vAD Cov We can a nS. t/2 pa (1 + cos 0) d de Ane 21T 4 sin 6 T Example

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• ##### Ruby negi

this is the solution...

• ##### Dhairya sharma

solution with circle r=2cos(thitha)

• ##### Abhishek singh Best Answer

solution is attached, if you got confused in calculation, do it once by yourself, you will definately get the same answer. Best regards.

thank u sir!

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