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30 a solid ab has naci type structure with edge length 580.4 pm. the radius of a is 100 pm. what is the radius of b ? (a) 190.2 (c) (b) (d) 540.13 78.12 525
30 A solid AB has NaCI type structure with edge length 580.4 pm. The radius of A is 100 pm. What is the radius of B ? (A) 190.2 (C) (B) (D) 540.13 78.12 525
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Reshav
can i apply this method because this relation is correct for nacl as fcc
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no, you can't apply because here NaCl type of lattice given and for NaCl there is different formula
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actually formula you've sent is only for FCC but here in NaCl there is octahedral voids also and Cl forms FCC lattice so there is different formula
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here 2r+ 2r-=a formula is valid
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i dont understand please explain more
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Priyanshu kumar
hope it helps😊🙏
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Priyanshu kumar Best Answer
see reshav
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i have shared a image please look at that and tell me why i cant apply that formula here?
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because thats also true for nacl as fcc
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okk let me see
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got reshav....as radius of atom = edge length/2...so you directly proceed by this formula...when edge length is given...as nacl has simple cubic crystal too in which anions is placed in face centered cubic array... so you can apply these formula as the formula you have mentioned you can use for fcc crystal system
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and radius of atom = radius of cation + radius of anion...so proceed directly
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Dinesh khalmaniya 1
hope this will help you 🙏
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Dinesh khalmaniya 1
option A
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Dinesh khalmaniya 1![best-answer]()
check this image for fomula of various ionic crystal
please accept the answer if you got it 🙏