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###### Smitarani Swain posted an Question
June 22, 2022 • 08:27 am 30 points
• IIT JAM
• Mathematics (MA)

# 4 (d'd+ d-d) : = 0. .(d+d-2d d)z=0. 6. (dd+d-3d')z= 0. (2d-d +4) (d+ 2d'+1)z=0. 8. (d-d-3d +3d) z =0. 9. (d-d-1) (d +d-2) z = 0. 10. (d-dd-2d) = 0. i irreducibl

4 (D'D+ D-D) : = 0. .(D+D-2D D)z=0. 6. (DD+D-3D')z= 0. (2D-D +4) (D+ 2D'+1)z=0. 8. (D-D-3D +3D) z =0. 9. (D-D-1) (D +D-2) z = 0. 10. (D-DD-2D) = 0. i Irreducible Equations. When the operator F (D, D') is irreducible, it is not always pos nd a solution with the exact number of arbitrary functions. How possible to construct solutions which contain infinite numbe rary constants. The method is described below. Consider the equation F (D, D) z = 0 ere F(D DM .4number question please solve

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• ##### Anonymous User

check

how to find CF in first method please tell me

D+mD')Z=0 THEN f(y-mx)

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