Shrigandha posted an Question
January 07, 2021 • 19:00 pm 30 points
  • IIT JAM
  • Chemistry (CY)

(408pm)3=? provide me with complete solution

(408pm)3=? provide me with complete solution . volume of unit cell

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    Priyanshu kumar

    This is only calculation part.. where you have problem in this...please ask

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    Dinesh khalmaniya 1

    1 pm = 10^-12m = 10^-12 × 100 cm = 10^-10 cm. So (408pm)3 = [(408)3× (10^-10)3]cm^3 (408pm)3 = [(6.79 ×10^7) (10^-30)]cm^3 = 6.79 × 10^-23 cm^3

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