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Nilanjan Bhowmick AIR 3, CSIR NET (Earth Science)
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check attachment 48 Z2+Z2=⟨(0,1),(1,0)⟩=⟨(1,0),(1,1)⟩=⟨(1,1),(0,1)⟩and these are only only generators with minimum no. of elements Now f is a automorphism on Z2×Z2 iff f sends any of these three basis-sets to another basis-sets. i.e. we have 3 choices of a basis-set to be image of f .Also for any of these choices we have 2 choices to pick a particular value of a element.i. e there are 6 automorphism(for example Consider f((0,1),(1,1))=(0,1),(1,0) . The RHS can be chosen 3 ways and each case can be done for 2 ways for f((0,1))=(0,1)or (1,0)) So|Aut(Z2×Z2)|=6 Also note that the maximum order of a element this group is 3 i.e Aut(Z2×Z2)≅S3
48) ????
plz wait
check 48