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Raunak Mitra posted an Question
June 13, 2020 • 18:48 pm 30 points
  • IIT JAM
  • Geology (GG)

51. the half life of a radionuclide a is double that of a radionuclide b. the fraction of a remaining when bis reduced to 1/64 is______

51. The half life of a radionuclide A is double that of a radionuclide B. The fraction of A remaining when Bis reduced to 1/64 is decimal places. Give answer in three

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    Rahul kumar

    Ans: 0.125 B is reduced to 1/64 means 6 half lifes of B have been passed. Now, half life of A is double than half life of B, so 6 half lifes of B means 3 half lifes of A. After 3 half lifes of A, the remaining fraction of A will be 1/8 (= 0.125).

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    Sajan sarthak Best Answer

    I have solved this in a simplified manner and i can also solve it by formula method. But the basic must be understood. if you want more i can show you by formula method give another question for it. Thank you

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    Thank you Sir.

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