Subrat posted an Question
January 15, 2022 • 00:15 am 30 points
  • IIT JAM
  • Physics (PH)

6 a 40k watt engine complete one cycle in 0.25 second. it burn 3.7g of petrol per second (e = 43.6 kjg'). it works between temperature 700°c and 27 c. what is e

6 A 40k watt engine complete one cycle in 0.25 second. It burn 3.7g of petrol per second (E = 43.6 kJg'). It works between temperature 700°C and 27 C. What is efficiency ? Contact Us: Website: www.eduncle.comEmail Support@ediinak

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  • Animesh anand Best Answer

    it is given that it burns 3.7g in 1 sec.so in 0.25sec it burns (3.7/0.25)g of petrol =0.925g .1g petrol require 43.6kj energy.so 0.925g of petrol require (0.925×43.6)kj energy =40.33kj. work done by engine in 0.25 sec is 10kj efficiency =work done/ heat absorbed =10/40.33=0.24 24 percent

    eduncle-logo-app

    that should be 3.7× 0.25

    eduncle-logo-app

    ya you are right

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