IIT JAM
Lalthazuala Asked a Question
August 27, 2020 10:20 ampts 30 pts
  • IIT JAM
  • Mathematics (MA)

6. dyldr =ry-xy. [gorakhpur 2005] ans. y =x+1 + ce 7. (dyldr) - y sec x =¥ sin x cos x. 8. dvldbx +y =xy'. [delhi b.sc. (hons) ii 2011] 9. x-) dr +21xy dy = 0.

6. dyldr =ry-xy. [Gorakhpur 2005] Ans. y =x+1 + ce 7. (dyldr) - y sec x =¥ sin x cos x. 8. dvldbx +y =xy'. [Delhi B.Sc. (Hons) II 2011] 9. x-) dr +21xy dy = 0. Ans. y' (sec x+tan x) = coS x- (x/2) +(1/4) sin 2x +C Ans. y=x + 1/2 +t ce Ans. y +x log (cr) =0
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  • Vishal goswami Best Answer
    see attachment question 6
    • cropped7282915367267071610.jpg
    Likes(0) Reply(1)
    Lalthazuala
    thank you so much
  • Vishal goswami thankyou
    see question 7
    • cropped8815770641159495816.jpg
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  • Deepak singh
    see attached
    • cropped1423687175.jpg
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    Lalthazuala
    thank you so much
  • Vishal goswami
    see 9
    • cropped6924681176221062962.jpg
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    Lalthazuala
    this question is equation reducible to linear form
  • Deepak singh
    attached 2
    • cropped89302956.jpg
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  • Vishal goswami
    see attachment question 8
    • cropped8366524027120184056.jpg
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  • Deepak singh
    any doubt then ask
    Likes(0) Reply(0)
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