Imdadul haque Asked a Question
September 13, 2020 10:05 ampts 30 pts
67. Consider the following electrochemical cel, from which current is drawn through an external resistor of 10 Ohms. During this process, the concentration of CusO, in the left and the right half-cells were measured, and the value of K=[CuSO4 hen /CuSO4lrighs Was calculated. From the initial value of K = 10. predict the value ofK after a very long time when the cell stopped giving any current. -Cul CusOatag, 10 M) || CusO4(aq. I M)Cu (a) An exact value cannot be predicted since CuSO4 solutions of such high concentrations, as used above, would not behave ideally. (b) K 0.1 (b) K= 1.0 (d) K will be very small. possibly < 0.00001.
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  • Anonymous User thankyou
    when K = 1 then only cell will Stop working
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  • Anonymous User
    option B is correct
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