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Reshav posted an Question
July 29, 2020 • 19:55 pm 30 points
  • IIT JAM
  • Chemistry (CY)

68% (+)- tartaric acid and 32% )- tartaric acid. ar unknow compound weighing4.2 gm is disso lved in enough carbon tetrachloride to make a total vo ume of 250 c.

68% (+)- tartaric acid and 32% )- tartaric acid. Ar unknow compound weighing4.2 gm is disso lved in enough carbon tetrachloride to make a total vo ume of 250 c.c. The observed rotation of this solution is +357.75° in a 25 cm cell using tne solnum D line. But if 4.2 gm is dissolved in 125 cc we observed rotation is +355.50°.Calculate st cific rotation for this compound. Avd to anantiomerY gave

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    Priyanshu kumar best-answer

    reshav check this

    cropped4974453882457998941.jpg
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    I have explained this na reshav

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    but sir its answer is -5.357 but from your calculations it comes out -53.57 please tell me how to solve it

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    reshav calculation is right it comes -53.57

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    got it reshav??

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    but sir iska answer - 5.357 hi ayega?how

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    reshav see the unit conversion ...it is also right....may be sometym answer is given wrong

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    please look at it image is not so clear but try to see ki isme sir ne -5.357 hi calculate kiya hai

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    but from this method iam not very clear

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    reshav 25 cm changes into 2.5 dm na...as length of cell is taken in dm

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    reshav see my solution in last part...if i take 25 cm as given in ques then ans comes -5.357 but you know we have to change 25 cm into dm which comes 2.5 dm..then the solution comes -53.57 ...so it is correct

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    now got it reshav??

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