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December 12, 2020 12:18 pmpts 30 pts
73. Ifa h (mod m; a bz (mod m) then: (A) q46, (mod ) (B) q- cbs (mod m) for any positive integer e (C) Both (A) and (B) (D) None of these 74. Ifa b(mod m), then for any integer n, we have: (A) a-b(mod nr") (B)a"-b" (mod m) (C) a"- b (mod x-a) (D) None of these 75. 1f ab (mod n), 0 sb
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