8. arrange the following in the correct order of acidity of the hydrogen indicated in bold. [jam 2009] (p) ( (d) p>r> iam 20no1 (a) p>q>r (b) r> q>p (c)q>r>p

in R negative charge delocalised into two rings make them aromatic which are further stabilized by 3 benzene rings. while in P and Q negative charge delocalised to one ring make it aromatic which are further stabilized by two benzene rings. but Q have extra resonance in compair to P

but sir according to anellation effect more no. of rings less aromaticity ?

Bht confusion hora sir plz clear my concept

Ab apne question ki baat krte he, yha pr case kuch alg he, P and Q me negative charge one five membered ring k sath aromaticity me participate kr rha he jbki R me two rings k sath aromaticity me participate kr rha he to anellation nhi bol skte. anellation to tb bolte jb sbhi structure me negative charge same rings k sath aromaticity me participate krta.

so negative charge R structure me sbse jada two rings ko aromatic bna rha he to sbse jada stability of carbanion hogi or sbse jada acidity.

got it??😊

ok Thanku

you welcome 🙏

but sir according to anellation effect I think option (a) should be correct

Q has more conjugation Than P so Q is more stable than P

R is most stable as 2 extra aromatic rings are formed

Toh isme anellation effect ni lgayenge ?

Directly you can see here after depronation which is stable....R is most stable as there is effective intra molecular H bonding

got this??