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Nilanjan Bhowmick AIR 3, CSIR NET (Earth Science)
Rituraj Borthakur posted an Question
February 08, 2023 • 00:40 am
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30 points
30 points
- IIT JAM
- Geology (GG)
87rb decays to 87sr with a decay constant lambda = 1.42 * 10 ^ - 11 per year. if at the time of formation, a system contains 8 * 10 ^ 4 atoms of 87rb and 103 at
87Rb decays to 87Sr with a decay constant lambda = 1.42 * 10 ^ - 11 per year. If at the time of formation, a system contains 8 * 10 ^ 4 atoms of 87Rb and 103 atoms of 87Sr, the number of 87 Sr atoms in this system at the end of 4 half-lives will be system evolution for parent-daughter pair. x103. Assume close
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Asif ali![best-answer]()
At time of Formation 87Rb (o) = N(o) = 8×10⁴ atoms 87Sr (o) = D(o) = 10³ atoms Sr (t) = ? since T = n.t/2 T = 4× 0.693/1.42×10-¹¹ T = 1.952×10¹¹ Years T = 1/Lambda.ln[(87Sr(t)-87Sr(o)/87Rb(t) ) +1] T.lambada = ln [87Sr(t)-10³+5×10³/0.5×10⁴] 15.99 = (87Sr(t) +4×10³)/0.5×10⁴ 87Sr(t) +4×10³ = 7.99529×10⁴ 87Sr(t) = (79.995-4)×10³ 87Sr(t) = 75.95 × 10³ atoms