30 points
>
>
Time management is very much important in IIT JAM. The eduncle test series for IIT JAM Mathematical Statistics helped me a lot in this portion. I am very thankful to the test series I bought from eduncle.
Nilanjan Bhowmick AIR 3, CSIR NET (Earth Science)
- IIT JAM
- Chemistry (CY)
9. for s and p valence orbitals, overlap decreases on a group of periodic table while b is true for the transition metals. that is why the heat of atomization o
9. For s and p valence orbitals, overlap decreases on A group of periodic table while B is true for the transition metals. That is why the heat of atomization of the main group metals C with increasing atomic numbers while B trend is observed for transition metals. Here A, B and C respectively are: (a) Ascending, opposite, increases (C) Descending, the same, geos up (b) descending, opposite, falls (d) ascending, the same, falls ANSWED KAV
2 Answer(s)
Answer Now
- 0 Likes
- 4 Comments
- 0 Shares
-
![comment-profile-img]()
>
-
![comment-profile-img]()
>
-
![comment-profile-img]()
>
Priyanshu kumar
![best-answer]()
Enthalpy of atomisation depend upon the number of unpaired electron more is unpaired electron more is enthalpy of atomisation.Upto the middle of the series, the number of unpaired electrons increases and then decreases due to their pairing. This results first in the increase and then decrease in the value of enthalpy of atomisation.So the enthalpy of atomisation of main group metals C-"falls" with increasing in atomic numbers and B- "opposite" trends is observed for transition metals.. So considering all these points..option B is correct
![eduncle-logo-app]()
Got this shristy??
![eduncle-logo-app]()
read this shristy👆...as in middle of series the enthalpy of atomisation increses for 3d series but for main grp metals it decreses...so falls and opposite...terms comes😊
-
![comment-profile-img]()
>
Priyanshu kumar Best Answer
Option B is correct
![eduncle-logo-app]()
explanation ??
![eduncle-logo-app]()
Going down a group, the atoms generally became larger, and the overlap between the valence orbitals of the bonded atoms decreases..And the opposite trends is observed for transition metals
![eduncle-logo-app]()
for 2nd part wait explaining typing....
![eduncle-logo-app]()
got it shristy??
![eduncle-logo-app]()
sir ye question hi smjh ni aara hme
![eduncle-logo-app]()
or enthalpy of atomisation no. of unpaired electrons pe depend krta hai...so in sabhi factors ko ek sath sentence me likh diya hai...down the group size large hota hai...so shape diffused ho jata hai....isiliye overalap effective nhi reh jata hai...wo decrease hota jata hai
![eduncle-logo-app]()
any doubt shristy you can ask😊
![eduncle-logo-app]()
N what for opposite and fall
![eduncle-logo-app]()
opposite means not the same trend for transition metal series
![eduncle-logo-app]()
this questions is combined and formed like a sentence
![eduncle-logo-app]()
you tell specific which part it creates problem?
![eduncle-logo-app]()
ok sir thanku
Do You Want Better RANK in Your Exam?
Start Your Preparations with Eduncle’s FREE Study Material
- Updated Syllabus, Paper Pattern & Full Exam Details
- Sample Theory of Most Important Topic
- Model Test Paper with Detailed Solutions
- Last 5 Years Question Papers & Answers
Sign Up to Download FREE Study Material Worth Rs. 500/-
Ashutosh singh
Due to increase in the sizes and principal quantum number, the d orbitals start coming in the picture. That's why it decreases while descending down the group. Hope it helps. 😊