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A) (b) 1 (c) 2 (d) 4 7. let g be a group of order 17. the total number of non-isomorphic
a) (b) 1 (c) 2 (d) 4 7. Let G be a group of order 17. The total number of non-isomorphic subgroups of
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Anonymous User Best Answer
Every group with an order p where p is prime is cyclic, indeed, isomorphic to Zp. Since 17 is prime, it's only divisors are 1,17. If there are subgroups of G, they must be of order 1, or order 17. we have the trivial subgroup containing the identity e∈G as its only element, and G itself. Clearly {e}≆G, since two groups whose orders differ cannot be isomorphic. B