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Santosh Behera posted an Question
January 20, 2021 • 14:14 pm 33 points
  • IIT JAM
  • Biotechnology (BT)

A bullet of mass 0.04 kg moving with a speed of 90 ms- enters a heavy wooden blodk and stopped after a distance of 60 cm. what is the average resistive force ex

A bullet of mass 0.04 kg moving with a speed of 90 ms- enters a heavy wooden blodk and stopped after a distance of 60 cm. What is the average resistive force exerted by the blodk an 19. the bullet? (A) 270 N (B) 170 N (C) 6750 N (D) 3270 N

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    Abhishek kumar singh

    option A is correct we have given V=0 (final velocity ) u =90 m/s s= 60cm= 0.6 m a= ?(retardation) from third equation of motion V² = u² - 2as ( since there is retardation) on solving this a = (90)²/2 × 0.6 = 6750 m/s² F = ma F = 0.04 kg × 6750 m/s² = 270 N

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