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Nilanjan Bhowmick AIR 3, CSIR NET (Earth Science)
Saurabh 1
It's simply based on the Darcy's law. We have, K= 50m/day hydraulic head (Or hydraulic gradient) = dh/dL = (45-40)/1000= 5/1000= 0.005 Area of the aquifer(A) = 30×5000= 150000m² So rate of flow (Q) is given by Q = V/t = KA(dh/dL) Q = 50×150000×0.005 = 37500 m³/day So, rate of flow through the aquifer is 37500 m³/day.