30 points
>
Time management is very much important in IIT JAM. The eduncle test series for IIT JAM Mathematical Statistics helped me a lot in this portion. I am very thankful to the test series I bought from eduncle.
Nilanjan Bhowmick AIR 3, CSIR NET (Earth Science)
- IIT JAM
- Biotechnology (BT)
(a) (d)18 15, the 50 ul of component e.coli cells (109 cfu/ml) were transformed using 0.5 mg of a 5 kb plasmid dna to which 950 ul of soc medium was added. only
(a) (D)18 15, The 50 uL of component E.coli cells (109 cfu/mL) were transformed using 0.5 mg of a 5 kb plasmid DNA to which 950 uL of soc medium was added. Only 50 uL of this was plated on a selective agar plate. After an 12 h incubation at 37°C, 90 colonies were observed. Calculate the percentage in transformed cells. (a) 0.36% (b) 0.72% (C) 3.6%% (d) 7.2%
1 Answer(s)
Answer Now
- 0 Likes
- 1 Comments
- 0 Shares
-
![comment-profile-img]()
>
Do You Want Better RANK in Your Exam?
Start Your Preparations with Eduncle’s FREE Study Material
- Updated Syllabus, Paper Pattern & Full Exam Details
- Sample Theory of Most Important Topic
- Model Test Paper with Detailed Solutions
- Last 5 Years Question Papers & Answers
Sign Up to Download FREE Study Material Worth Rs. 500/-
Krishan k jakhad![best-answer]()
c. 3.6% Transformation efficiency (TE) equation: TE = Colonies/µg/Dilution Colonies = the number of colonies counted on the plate µg = the amount of DNA transformed expressed in µg Dilution = the total dilution of the DNA before plating given Colonies = 90 µg DNA = 0.5 mg or 500 micrograms Dilution = 50/1000=0.05 TE = 90/500/0.05 = 3.6 cfu/µg