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Nilanjan Bhowmick AIR 3, CSIR NET (Earth Science)
- IIT JAM
- Biotechnology (BT)
A eukaryotic gene of 1000 base pairs containing several introns encodes a protein of 11 kda. assuming that the average molecular weight of one amino acid is 110
A eukaryotic gene of 1000 base pairs containing several introns encodes a protein of 11 kDa. Assuming that the average molecular weight of one amino acid is 110 Da, the total length (in base pairs) of all the introns of the gene is approximately 11. a. 700 b. 100 C. 650 d. 1000
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Dr. sharad agrawal![best-answer]()
correct answer should be 697. bcoz, 11000 da protein / 110 (mol wt of each a.a.) = 100 amino acids in total. and each amino acid is coded by 3 nucleotide so 300 nucleotides are coding for the entire protein. plus during the formation of transcript, one stop codon should be there, so total nucleotides =303. now 1000 - 303 = 697 since 697 option is not given, 700 should be the right answer