IIT JAM
Khyati Asked a Question
May 29, 2021 11:06 pmpts 30 pts
  • IIT JAM
  • Mathematics (MA)

A function f is detined on interval (0, 1) as follows when x is irrational f(x) =1 when x is rational no.and lcm(p,q) =1 then which one of the following is true

it should be discontinuous at each and every point because there are infinite number of rational and irrational no in interval (0,1) then why it's continuous at each irrational points?
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  • Alka gupta thankyou
    f(x) is discontinuous at every rational and irrational numbers... because in nbd of rational number infinitely many rational and irrational numbers. similarly in nbd of an irratio...
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    Khyati
    yes mam that's my point too.......but...
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