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Nilanjan Bhowmick AIR 3, CSIR NET (Earth Science)
Nayansi gupta
F1=2.0cm\\\\\\\\\\\\\\\\nF2=6.25cm\\\\\\\\\\\\\\\\distance (d)= 15.0cm\\\\\\\\nV2= -25cm\\\\n1/V2=1/U2 + 1/F2\\\\n1/U2 = 1/V2 - 1/F2\\\\n =1/-25- 1/6.25\\n=-1-4/25\\n=-5/25\\nU2=-5cm\nV1=d+U2\n =15-5=10\nV1=10cm\n1/U1=1/V1-1/F1\n =1/10-1/2\n =-4/10 =-2.5 U1=-2.5cm