Shivanantham posted an Question
September 08, 2021 • 16:48 pm 30 points
  • IIT JAM
  • Physics (PH)

A particle of mass 4 m which is at rest explodes into three fragments. two of the fragments each of mass m are found to move with a speed v each in mutually per

A particle of mass 4 m which is at rest explodes into three fragments. Two of the fragments each of mass m are found to move with a speed v each in mutually perpendicular directions. The energy released in the process of explosion is n (A) my2 (O (B) my nisto mmolinu A vlsoihov pripasr (C) mv None of these oli(D)

2 Answer(s) Answer Now
  • 0 Likes
  • 3 Comments
  • 0 Shares
  • comment-profile-img>
    Anshum Sharma

    So final Kinetic energy = K.E¹ + K.E² + K.E³ then subtract from initial Kinetic energy

  • comment-profile-img>
    Anshum Sharma Best Answer

    To find the energy released in explosion, You have to find the difference initial and final Kinetic energies, so that is why you have to calculate the momentum of all the masses.

whatsapp-btn

Do You Want Better RANK in Your Exam?

Start Your Preparations with Eduncle’s FREE Study Material

  • Updated Syllabus, Paper Pattern & Full Exam Details
  • Sample Theory of Most Important Topic
  • Model Test Paper with Detailed Solutions
  • Last 5 Years Question Papers & Answers