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Syed Shoaib posted an Question
November 02, 2021 • 13:36 pm 30 points
  • IIT JAM
  • Physics (PH)

A particle of mass m in the potential v(x, y)=mo|4x* + y*), is in an eigenstate of energy e ho. the corresponding un-normalized eigen function is ( yexp22r+y')|

A particle of mass m in the potential V(x, y)=mo|4x* + y*), is in an eigenstate of energy E ho. The corresponding un-normalized eigen function is ( yexp22r+y')| (b) xexper+) () yexp2+) (d) yexp + 2h

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    Anshum Sharma

    Here is the detailed solution option (a) is the correct

    cropped8757225995831779216.jpg
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