Vidushi Saklani posted an Question
October 30, 2021 • 13:36 pm 10 points
  • IIT JAM
  • Physics (PH)

A particle of mass m moves under the action of a central force whose potential is v() = kme (k > 0), then energy for which the orbit will be a circle of radius

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    Anshum Sharma best-answer

    Because this is attractive force and we consider a sign convention that when a body is attracted then we take (-ve) sign

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    Anshum Sharma

    Here is the detailed solution

    cropped4238634578576465466.jpg
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    this is the solution given but central force is equal to negative of dv(r)/dr so why haven't they consider negative sign

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    these are the options given

  • Vidushi saklani

    this is the solution given but central force is equal to negative of dv(r)/dr so why haven't they consider negative sign

    cropped1018099550722922167.jpg
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