A pas fcl l_ 8ubiected to a nnstawt fena tho ds placemment veus m plot fax oelativístic motion_ wiu ae a)stsaigut n cc) ypeibelie cb)pasabelic cd) cules am

answer is hyperbolicc.. try to do it by urself using F=dp/dt----> integrate---->p=Ft+c-----> c=0----->p=Ft----->mv=Ft-----> m is mo*gamma,you know gamma----> now put m and separa...

force is constant, so acceleration is also constant. from equation s=ut+1/2at^2 we can say that the graph between displacement and time will be a parabola. option (b) is correct

hyperbola, F = dp/dt, p = gamma ×m×v