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Nilanjan Bhowmick AIR 3, CSIR NET (Earth Science)
Gauri Upadhye posted an Question
November 14, 2021 • 22:46 pm
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30 points
30 points
- IIT JAM
- Biotechnology (BT)
A person can throw a ball to a maximum horizontal distance of 90 m calculate the maximum vertical height to which he can throw the ball
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Priya sarda
Maximum horizontal distance, R=90m The cricketer will only be able to throw the ball to the maximum horizontal distance when the angle of projection is 45∘, i.e., =45∘. The max horizontal range for a projection velocity v is given by the relation: Rmax=gu2 90=gu2 The ball will achieve the maximum height when it is thrown vertically upward. For such motion, the final velocity v is zero at the maximum height H. Acceleration, a=g Using the third equation of motion: v2−u2=−2gH H=u2/2g=90/2=45m
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Priya sarda
Maximum horizontal distance, R=90m The cricketer will only be able to throw the ball to the maximum horizontal distance when the angle of projection is 45∘, i.e., =45∘. The max horizontal range for a projection velocity v is given by the relation: Rmax=gu2 90=gu2 The ball will achieve the maximum height when it is thrown vertically upward. For such motion, the final velocity v is zero at the maximum height H. Acceleration, a=g Using the third equation of motion: v2−u2=−2gH H=u2/2g=90/2=45m
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Priya sarda
Maximum horizontal distance, R=90m The cricketer will only be able to throw the ball to the maximum horizontal distance when the angle of projection is 45∘, i.e., =45∘. The max horizontal range for a projection velocity v is given by the relation: Rmax=gu2 90=gu2 The ball will achieve the maximum height when it is thrown vertically upward. For such motion, the final velocity v is zero at the maximum height H. Acceleration, a=g Using the third equation of motion: v2−u2=−2gH H=u2/2g=90/2=45m
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Priya sarda
Maximum horizontal distance, R=90m The cricketer will only be able to throw the ball to the maximum horizontal distance when the angle of projection is 45∘, i.e., =45∘. The max horizontal range for a projection velocity v is given by the relation: Rmax=gu2 90=gu2 The ball will achieve the maximum height when it is thrown vertically upward. For such motion, the final velocity v is zero at the maximum height H. Acceleration, a=g Using the third equation of motion: v2−u2=−2gH H=u2/2g=90/2=45m
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Priya sarda Best Answer
Maximum horizontal distance, R=90m The cricketer will only be able to throw the ball to the maximum horizontal distance when the angle of projection is 45∘, i.e., =45∘. The max horizontal range for a projection velocity v is given by the relation: Rmax=gu2 90=gu2 The ball will achieve the maximum height when it is thrown vertically upward. For such motion, the final velocity v is zero at the maximum height H. Acceleration, a=g Using the third equation of motion: v2−u2=−2gH H=u2/2g=90/2=45m
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Priya sarda
Maximum horizontal distance, R=90m The cricketer will only be able to throw the ball to the maximum horizontal distance when the angle of projection is 45∘, i.e., =45∘. The max horizontal range for a projection velocity v is given by the relation: Rmax=gu2 90=gu2 The ball will achieve the maximum height when it is thrown vertically upward. For such motion, the final velocity v is zero at the maximum height H. Acceleration, a=g Using the third equation of motion: v2−u2=−2gH H=u2/2g=90/2=45m