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Nilanjan Bhowmick AIR 3, CSIR NET (Earth Science)
Ravi bhushan Best Answer
a) Here, f = - 20 cm = - 0.2 m The power of the lense will be P = 1/f P = 1/(-0.2) = - 5 D
Can you please explain part b
I mean I don't understand what force the question is about
I am asking you what is the use of force in Optics.
I also having the same problem regarding the question
Part B is confusing therefore I have not given the solution of part B.
Ok
Can part b assmed that calculate the power of replaced glasses which are placed 1.5cm from eye
Will the focal length decrease by 1.5cm or increase by 1.5cm