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###### Surya posted an Question
March 10, 2022 • 22:06 pm 30 points
• IIT JAM
• Physics (PH)

# A person is very nearsighted and has a far point (a). (20cm) what is the strength of contact lenses (when on the eye) that will correct his far vision? (b) what

A person is very nearsighted and has a far point (a). (20cm) What is the strength of contact lenses (when on the eye) that will correct his far vision? (b) What is the force if the contact lenses are replaced with glasses located 1.5 cm from the eye.

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• ##### Ravi bhushan Best Answer

a) Here, f = - 20 cm = - 0.2 m The power of the lense will be P = 1/f P = 1/(-0.2) = - 5 D

Can you please explain part b

I mean I don't understand what force the question is about

I am asking you what is the use of force in Optics.

I also having the same problem regarding the question

Part B is confusing therefore I have not given the solution of part B.

Ok

Can part b assmed that calculate the power of replaced glasses which are placed 1.5cm from eye

Will the focal length decrease by 1.5cm or increase by 1.5cm

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