Anukruti posted an Question
October 26, 2020 • 01:31 am 30 points
  • IIT JAM
  • Geology (GG)

A slip lineation on a fault plane has a rake of 68°.this fault is oriented at n52°e,83°se.what is the plunge and bearing of this lineation?

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    Rahul kumar best-answer

    For calculation of Plunge amount: sin(plunge) = sin(dip) × sin(rake) sin(plunge) = sin(83) × sin(68) = 0.92 So, Plunge= arcsin(0.92) = 66.92° i.e., the plunge of lineation is 66.92° For calculation of bearing (relative to strike direction of bed): cos(bearing) = cos(rake) / cos(plunge) cos(bearing)= cos(68) / cos(66.92) = 0.95559 Bearing= arccos(0.95559)= 17.14° So, the actual bearing of lineation= Bearing relative to strike of the bed + strike of the bed = 17.14° + N52E = N69.14E i.e., the actual bearing of lineation is N69.14E

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    Sajan sarthak Best Answer

    Plunge is 67 ° and bearing may be 069 or 215 because that lineation can be from any side if plane

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