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Nilanjan Bhowmick AIR 3, CSIR NET (Earth Science)
- IIT JAM
- Chemistry (CY)
A solution containing na,co3 and naoh requires 300 ml of 0.1 n hci using phenolphthalein as an indicator. methyl or
natak ataka CET) ka CET) (Karnataka CE) 132. A solution containing Na,CO3 and NaOH requires 300 mL of 0.1 N HCI using phenolphthalein as an indicator. Methyl orange is then added to above titrated solution when a further 25 mL of 0.2 N HCIis required. The amount of NaOH present in the original (Karna solution is (a) 0.5g (c) 2g (b) 1g (d) 4g (OJEE)
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Dinesh khalmaniya 1
The reaction are as follows: NaOH+HCl→NaCl+H2O Na2CO3+HCl→2NaCl+CO2+H2O Phenolphthalein changes its color when the solution becomes neutral i.e. when all the base is consumed and half of the sodium carbonate is converted to sodium hydrogen carbonate. So, we can say, 300 ml HCl of 0.1N HCl neutralizes the entire amount of NaOH and half of Na2CO3. As given, 50ml of 0.1N (which is equal to 25 ml of 0.2N) of HCl is utilized to neutralize the remaining half of Na2CO3. So, 250 ml (300−50 ml) of 0.1N of HCl is required to neutralize NaOH completely. As number of milliequivalents of HCl= number of milliequivalents of NaOH ⇒250×0.1 meq of HCl=250×0.1 meq of NaOH which is equal to 25 milimoles of NaOH, which in turn, is equal to 1 g of NaOH.
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Priyanshu kumar
hope this video helps😊🙏
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Priyanshu kumar Best Answer
https://doubtnut.com/question-answer-chemistry/a-solution-containing-na2co3-and-naoh-requires-300-ml-of-01-n-hcl-using-phenolphthalein-as-an-indica-12224901 for video solution
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Suman Kumar
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See this
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Priyanshu kumar
check this
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Dinesh khalmaniya 1
hope this will help you 🙏