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Vavaiya Vaibhavkumar posted an Question
September 04, 2021 • 19:11 pm
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30 points
30 points
- IIT JAM
- Physics (PH)
A thermally insulated cubical box has two chambers of equal volume. initially one mole of a monoatomic ideal gas is placed olin one of the chamber while the oth
A Thermally insulated cubical box has two chambers of equal volume. Initially one mole of a monoatomic ideal gas is placed olin one of the chamber while the other chamber is kept empty. The gas slowly leaks through a small hole and eventually occupies the whotbox. The change in entropy of the gas is given by
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Isha lohan 1![best-answer]()
This is the case of adiabatic mixing of two gases, where one side is to be considered as empty. The change of entropy in this case is to be calculated by, del S = nRT*ln(V{final} / Vinitial). As the monoatomic gas volume doubled over time so, it's entropy change will be, =nRT*ln2 While other chamber has zero volume of initial gas so it's entropy change is taken to be zero. So net entropy change here is, =nRT*ln2. This formula is to be used with ideal gases. Not real gases. In real gases, equation of pressure relation will be given and you have to do, Del(S) = del P / del V.
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