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Nilanjan Bhowmick AIR 3, CSIR NET (Earth Science)
Isha lohan 1
This is the case of adiabatic mixing of two gases, where one side is to be considered as empty. The change of entropy in this case is to be calculated by, del S = nRT*ln(V{final} / Vinitial). As the monoatomic gas volume doubled over time so, it's entropy change will be, =nRT*ln2 While other chamber has zero volume of initial gas so it's entropy change is taken to be zero. So net entropy change here is, =nRT*ln2. This formula is to be used with ideal gases. Not real gases. In real gases, equation of pressure relation will be given and you have to do, Del(S) = del P / del V.
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