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Isha Lohan posted an Question
January 09, 2021 • 03:24 am 30 points
  • IIT JAM
  • Physics (PH)

A vessel containing equal umber of molecules of two monoatomic gases a and b is at temperatures t. their masses are m and 4m respectively. the root mean squared

A vessel containing equal umber of molecules of two monoatomic gases A and B is at temperatures T. Their masses are m and 4m respectively. The root mean squared velocity of the atoms in the mixtureis 3 3 16kT 3 SkT (a) 4 m 8kT (b) 16kT (d) 5 m 5 7m

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    Dhairya sharma Best Answer

    ans should be option a

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    mam how you get this?

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    see attached

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    this 8 by pie term comes in average velocity. but in ques it is asking root mean squared velocity. is it correct to take v1 and v2 to be average velocities?

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    he root mean square (rms) is always equal or higher than the average (avg). Only if all numbers in the list are positive and equal then rms = avg. The reason is that higher values in the list have a higher weight (because you average the squares) in the calculation of a rms compared to the calculation of the avg. So only if all molecules have the same velocity we would have: V(rms) = V(avg). However, at least in ideal gases, the velocities of the molecules are distributed according to the Maxwell-Boltzmann distribution. For the Maxwell-Boltzmann distribution holds: V(rms) = V(ave)*sqrt(3/8*pi)

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