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Nilanjan Bhowmick AIR 3, CSIR NET (Earth Science)
Suman Kumar
i>ii>iii. This will be the order of basicity
ist is more basic as it is bridged and sp3 Nitrogen
2nd is more basic than 3rd as its lone pair is localized here. Due to bridging N lone can't participate in delocalization.
3rd is least basic due to participation in resonance
Please ask if you don't get
but sir 2 is doing resonance na?
2 can't do resonance Sourav. Nitrogen bridging ke karan pahle hi strain me hai.
ok.. how to see btw 1 and 2..dono lone pair reso mai part nahi le rahe
You must have studied bridged carbocation are highly unstable
1 me Nitrogen ke adjacent sp3 carbon.
2 me Nitrogen ke adjacent me phenyl ring hai jo ki sp2 hybridized hai so -I effect
one more qs, if 2 and 1 are bridged how they will donate lone pair sir.. they will became unstable na.So 3 should be more stable as no bridging is present
by donation bridge atom will become sp2
Donation se sp2 kaise ?
sir agar bridge head pe +ve charge hoga.. to woh unstable nahi hoga.. only sp2 hone par unstable hoga?
carbocation sp2 hi hote hai
mai ye +ve charge ki bat kr rha sir. Ye stable hoga Bridge head pe?
Are yaar ye carbocation hai btao Sourav. Yeh to formal charge . Carbocation to Eletron deficient species hai dear
ok sir got it.. my doubt was that will all positive charge on bridge head will be unstable or not. 😊
Whatever i know should be delivered to you. That's all. 😊
Happy learning