Shrigandha Asked a Question
May 6, 2021 4:54 pmpts 30 pts
[Ag [Ag'] = 10-8.428 or, = 0.37 x 10-8 mol dm-3 Ex. Calculate the K of Agl by forming proper cell. Given rAgls)Ag9 = -0.151 V and EA0.7991 V. AgAg Sol. The cell can be written as Ag | Ag; F|Agl | Ag At left electrode E E- E = -0.151 0.7991 Unc Ag (s) Ag* + e, E° = 0.7991 V At right electrode Agl(s) + e Ag(s) + F E° = -0.151 V Agl(s) > Agt + F The standard emf of the cell is = -0.9501 V We know that (0.9501)(1) log K 0.059 -16.1 K 10-16.1 7.94x 10-17 ootrioithr ie callec
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  • Shrigandha
    I understand whole problem except last one convertation
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  • Shrigandha
    please tell me how to get solubility product
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  • Shrigandha
    I understand whole problem except last solubility product
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  • Shrigandha
    how to get solubility product
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  • Shrigandha
    how to do solubility product
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  • Bhagat singh thankyou
    answer.
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