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Payal posted an Question

September 01, 2020 • 15:43 pm

30 points

IIT JAM
Chemistry (CY)

Along the period the atomic radius of 3rd transition series

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Priyanshu kumar Best Answer

Option D This is because initially the Nuclear charge increases like normal trend And hence the radii decreases continuously. From the middle… or ending of middle the Nuclear charge equates with the inter electronic repulsion and hence no such inc of radii takes place…. And finally …. Radii increases due to increase of inter electronic repulsions more than Zeff…This occurs in 3d ,4d and 5d
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First decreases then remain constant in the middle then again increases in the last
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Option D is correct
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Got this??
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see
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yes sir
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thank you
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welcome😊
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Dinesh khalmaniya 1

option D In case of d block elements as we move from left to right across the period, atomic number increases. The nuclear charge increases. But the electrons are added to penultimate i.e. (n-1) shell, hence the electron cloud density of inner shells increases which increases the screening effect. Thus nuclear charge increases and screening effect increases. Hence there is decreases in the atomic radius but the extent of variation is very small compared to s block and p block elements. The extent of variation is so small that all of them can be considered to have almost equal atomic radii.
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From Ni to Zn, Zeffeff decreases and the shielding effect increases . Zeffeff is inversely proportional to the size, so if Zeffeff decreases, size will increase. That's why there is some uncertainty in the order of size for 3d series.
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so option D is correct
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got it??
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check it also
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thank you sir
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