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Among chf3, chcl3, chbr3 why backbonding is possible only for 2nd one
among CHF3, CHCl3, CHBr3 why backbonding is possible only for 2nd one
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Suman Kumar
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Dinesh khalmaniya 1
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Dinesh khalmaniya 1 Best Answer
check this concept CHCl3> CHBr3>CHI3>CHF3 ie decreasing order of acidic strength Explanation: I think you already know that halogen show both Inductive and Mesomeric effect. In the given question we have to compare the acidic strength, so in order to check it first make anion of all these and check their stability acc. To most prefential factor (ie either inductive or mesomeric) As here most prefered is Mesomeric. In CHCl3 the anion formed after removal of H is more stable to to back donation ( as the cl, br and Ihave vacant d orbital) but as we move from cl to iodine the extent or rate of this back donation tedency decrease ( 2s-3p, 2s-4p and 2S-5P overlapping respectively) . Also in case f there is no vacant orbital ( neither d nor p) so no back donation thus the anion formed from CHF3 is least stable among all.
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Priyanshu kumar![best-answer]()
In CHCl3 the anion formed after removal of H is more stable to to back donation ( as the cl, br and Ihave vacant d orbital) but as we move from cl to iodine the extent or rate of this back donation tedency decrease ( 2s-3p, 2s-4p and 2S-5P overlapping respectively) . Also in case f there is no vacant orbital ( neither d nor p) so no back donation thus the anion formed from CHF3 is least stable among all
effective overlapping occurs in case of CHCl3...so back donation is more...so more acidic...which decreases down the group....
got this???